Optimal. Leaf size=168 \[ -\frac{2 b^3 \left (4 a^2-3 b^2\right ) \tan ^{-1}\left (\frac{a \tan \left (\frac{x}{2}\right )+b}{\sqrt{a^2-b^2}}\right )}{a^4 \left (a^2-b^2\right )^{3/2}}+\frac{b \left (2 a^2-3 b^2\right ) \cot (x)}{a^3 \left (a^2-b^2\right )}-\frac{\left (a^2+6 b^2\right ) \tanh ^{-1}(\cos (x))}{2 a^4}-\frac{\left (a^2-3 b^2\right ) \cot (x) \csc (x)}{2 a^2 \left (a^2-b^2\right )}-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))} \]
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Rubi [A] time = 0.574429, antiderivative size = 168, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.538, Rules used = {2802, 3055, 3001, 3770, 2660, 618, 204} \[ -\frac{2 b^3 \left (4 a^2-3 b^2\right ) \tan ^{-1}\left (\frac{a \tan \left (\frac{x}{2}\right )+b}{\sqrt{a^2-b^2}}\right )}{a^4 \left (a^2-b^2\right )^{3/2}}+\frac{b \left (2 a^2-3 b^2\right ) \cot (x)}{a^3 \left (a^2-b^2\right )}-\frac{\left (a^2+6 b^2\right ) \tanh ^{-1}(\cos (x))}{2 a^4}-\frac{\left (a^2-3 b^2\right ) \cot (x) \csc (x)}{2 a^2 \left (a^2-b^2\right )}-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))} \]
Antiderivative was successfully verified.
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Rule 2802
Rule 3055
Rule 3001
Rule 3770
Rule 2660
Rule 618
Rule 204
Rubi steps
\begin{align*} \int \frac{\csc ^3(x)}{(a+b \sin (x))^2} \, dx &=-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))}+\frac{\int \frac{\csc ^3(x) \left (a^2-3 b^2-a b \sin (x)+2 b^2 \sin ^2(x)\right )}{a+b \sin (x)} \, dx}{a \left (a^2-b^2\right )}\\ &=-\frac{\left (a^2-3 b^2\right ) \cot (x) \csc (x)}{2 a^2 \left (a^2-b^2\right )}-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))}+\frac{\int \frac{\csc ^2(x) \left (-2 b \left (2 a^2-3 b^2\right )+a \left (a^2+b^2\right ) \sin (x)+b \left (a^2-3 b^2\right ) \sin ^2(x)\right )}{a+b \sin (x)} \, dx}{2 a^2 \left (a^2-b^2\right )}\\ &=\frac{b \left (2 a^2-3 b^2\right ) \cot (x)}{a^3 \left (a^2-b^2\right )}-\frac{\left (a^2-3 b^2\right ) \cot (x) \csc (x)}{2 a^2 \left (a^2-b^2\right )}-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))}+\frac{\int \frac{\csc (x) \left (a^4+5 a^2 b^2-6 b^4+a b \left (a^2-3 b^2\right ) \sin (x)\right )}{a+b \sin (x)} \, dx}{2 a^3 \left (a^2-b^2\right )}\\ &=\frac{b \left (2 a^2-3 b^2\right ) \cot (x)}{a^3 \left (a^2-b^2\right )}-\frac{\left (a^2-3 b^2\right ) \cot (x) \csc (x)}{2 a^2 \left (a^2-b^2\right )}-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))}-\frac{\left (b^3 \left (4 a^2-3 b^2\right )\right ) \int \frac{1}{a+b \sin (x)} \, dx}{a^4 \left (a^2-b^2\right )}+\frac{\left (a^2+6 b^2\right ) \int \csc (x) \, dx}{2 a^4}\\ &=-\frac{\left (a^2+6 b^2\right ) \tanh ^{-1}(\cos (x))}{2 a^4}+\frac{b \left (2 a^2-3 b^2\right ) \cot (x)}{a^3 \left (a^2-b^2\right )}-\frac{\left (a^2-3 b^2\right ) \cot (x) \csc (x)}{2 a^2 \left (a^2-b^2\right )}-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))}-\frac{\left (2 b^3 \left (4 a^2-3 b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac{x}{2}\right )\right )}{a^4 \left (a^2-b^2\right )}\\ &=-\frac{\left (a^2+6 b^2\right ) \tanh ^{-1}(\cos (x))}{2 a^4}+\frac{b \left (2 a^2-3 b^2\right ) \cot (x)}{a^3 \left (a^2-b^2\right )}-\frac{\left (a^2-3 b^2\right ) \cot (x) \csc (x)}{2 a^2 \left (a^2-b^2\right )}-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))}+\frac{\left (4 b^3 \left (4 a^2-3 b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac{x}{2}\right )\right )}{a^4 \left (a^2-b^2\right )}\\ &=-\frac{2 b^3 \left (4 a^2-3 b^2\right ) \tan ^{-1}\left (\frac{b+a \tan \left (\frac{x}{2}\right )}{\sqrt{a^2-b^2}}\right )}{a^4 \left (a^2-b^2\right )^{3/2}}-\frac{\left (a^2+6 b^2\right ) \tanh ^{-1}(\cos (x))}{2 a^4}+\frac{b \left (2 a^2-3 b^2\right ) \cot (x)}{a^3 \left (a^2-b^2\right )}-\frac{\left (a^2-3 b^2\right ) \cot (x) \csc (x)}{2 a^2 \left (a^2-b^2\right )}-\frac{b^2 \cot (x) \csc (x)}{a \left (a^2-b^2\right ) (a+b \sin (x))}\\ \end{align*}
Mathematica [A] time = 0.864321, size = 171, normalized size = 1.02 \[ \frac{\frac{16 b^3 \left (3 b^2-4 a^2\right ) \tan ^{-1}\left (\frac{a \tan \left (\frac{x}{2}\right )+b}{\sqrt{a^2-b^2}}\right )}{\left (a^2-b^2\right )^{3/2}}+4 \left (a^2+6 b^2\right ) \log \left (\sin \left (\frac{x}{2}\right )\right )-4 \left (a^2+6 b^2\right ) \log \left (\cos \left (\frac{x}{2}\right )\right )-a^2 \csc ^2\left (\frac{x}{2}\right )+a^2 \sec ^2\left (\frac{x}{2}\right )-\frac{8 a b^4 \cos (x)}{(a-b) (a+b) (a+b \sin (x))}-8 a b \tan \left (\frac{x}{2}\right )+8 a b \cot \left (\frac{x}{2}\right )}{8 a^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.075, size = 236, normalized size = 1.4 \begin{align*}{\frac{1}{8\,{a}^{2}} \left ( \tan \left ({\frac{x}{2}} \right ) \right ) ^{2}}-{\frac{b}{{a}^{3}}\tan \left ({\frac{x}{2}} \right ) }-2\,{\frac{{b}^{5}\tan \left ( x/2 \right ) }{{a}^{4} \left ( \left ( \tan \left ( x/2 \right ) \right ) ^{2}a+2\,\tan \left ( x/2 \right ) b+a \right ) \left ({a}^{2}-{b}^{2} \right ) }}-2\,{\frac{{b}^{4}}{{a}^{3} \left ( \left ( \tan \left ( x/2 \right ) \right ) ^{2}a+2\,\tan \left ( x/2 \right ) b+a \right ) \left ({a}^{2}-{b}^{2} \right ) }}-8\,{\frac{{b}^{3}}{{a}^{2} \left ({a}^{2}-{b}^{2} \right ) ^{3/2}}\arctan \left ( 1/2\,{\frac{2\,a\tan \left ( x/2 \right ) +2\,b}{\sqrt{{a}^{2}-{b}^{2}}}} \right ) }+6\,{\frac{{b}^{5}}{{a}^{4} \left ({a}^{2}-{b}^{2} \right ) ^{3/2}}\arctan \left ( 1/2\,{\frac{2\,a\tan \left ( x/2 \right ) +2\,b}{\sqrt{{a}^{2}-{b}^{2}}}} \right ) }-{\frac{1}{8\,{a}^{2}} \left ( \tan \left ({\frac{x}{2}} \right ) \right ) ^{-2}}+{\frac{1}{2\,{a}^{2}}\ln \left ( \tan \left ({\frac{x}{2}} \right ) \right ) }+3\,{\frac{\ln \left ( \tan \left ( x/2 \right ) \right ){b}^{2}}{{a}^{4}}}+{\frac{b}{{a}^{3}} \left ( \tan \left ({\frac{x}{2}} \right ) \right ) ^{-1}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 6.92116, size = 2635, normalized size = 15.68 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\csc ^{3}{\left (x \right )}}{\left (a + b \sin{\left (x \right )}\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.60396, size = 290, normalized size = 1.73 \begin{align*} -\frac{2 \,{\left (4 \, a^{2} b^{3} - 3 \, b^{5}\right )}{\left (\pi \left \lfloor \frac{x}{2 \, \pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (a\right ) + \arctan \left (\frac{a \tan \left (\frac{1}{2} \, x\right ) + b}{\sqrt{a^{2} - b^{2}}}\right )\right )}}{{\left (a^{6} - a^{4} b^{2}\right )} \sqrt{a^{2} - b^{2}}} - \frac{2 \,{\left (b^{5} \tan \left (\frac{1}{2} \, x\right ) + a b^{4}\right )}}{{\left (a^{6} - a^{4} b^{2}\right )}{\left (a \tan \left (\frac{1}{2} \, x\right )^{2} + 2 \, b \tan \left (\frac{1}{2} \, x\right ) + a\right )}} + \frac{{\left (a^{2} + 6 \, b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, x\right ) \right |}\right )}{2 \, a^{4}} + \frac{a^{2} \tan \left (\frac{1}{2} \, x\right )^{2} - 8 \, a b \tan \left (\frac{1}{2} \, x\right )}{8 \, a^{4}} - \frac{6 \, a^{2} \tan \left (\frac{1}{2} \, x\right )^{2} + 36 \, b^{2} \tan \left (\frac{1}{2} \, x\right )^{2} - 8 \, a b \tan \left (\frac{1}{2} \, x\right ) + a^{2}}{8 \, a^{4} \tan \left (\frac{1}{2} \, x\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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